Answer:
V = -0.4 m/s
Explanation:
Given that,
Mass of cart 1, m₁ = 3 kg
Speed of cart 1, v₁ = 2 m/s
Mass of cart 2, m₂ = 2 kg
Speed of cart 2, v₂ = -4 m/s (left)
aWe need to find the velocity of the carts after the collision if they stick together. Let the common speed be V. Using the law of conservation of momentum to find it such that,
[tex]m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}[/tex]
Put all the values,
[tex]V=\dfrac{3\times 2+2\times (-4)}{(3+2)}\\\\=-0.4\ m/s[/tex]
So, the velocity of the carts after the collision is equal to 0.4 m/s to the left.
