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What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?
0 1 = 0.01 A
0 1 = 0.8 A
0 1 = 80 A
O I = 0.08 A

Respuesta :

theleangreenbean

Answer:

80 A

Explanation:

Hi there!

Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I

[tex]V=IR\\0.8=I(0.01)[/tex]

Divide both sides by  0.01 to isolate I

[tex]0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I[/tex]

Therefore, the current for this circuit would be 80 A.

I hope this helps!

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