Consider a taxi station at an airport where taxis and (groups of) customers arrive at times of Poisson processes with rates 2 and 3 per minute. Suppose that a taxi will wait no matter how many other taxis are present. However, if an arriving person does not find a taxi waiting he leaves to find alternative transportation. (a) Find the proportion of arriving customers that get taxis. (b) Find the average number of taxis waiting

Respuesta :

Answer:

a) [tex]\pi(0)=\frac{1}{3}[/tex]

b) [tex]X=\frac{2}{3}[/tex]

Step-by-step explanation:

From the question we are told that:

Arrival time with Poisson's process =[tex]t_p=2-3minutes[/tex]

where

[tex]\lambda_1=2\\\lambda_2=3[/tex]

a)

Generally the equation Poisson's process is mathematically given by

[tex]\pi()n*\lambda_1=\pi(n+1*) \lambda_2[/tex]

[tex]\pi()n*2=\pi(n+1*)*3[/tex]

[tex]\pi(n+1)=\frac{2}{3} \pi+1*\pi(0)[/tex]

Therefore

[tex]\pi(0)(1+2/3+(2/3)^2+...)=1[/tex]

[tex]\pi(0)=\frac{1}{3}[/tex]

The proportion of arriving customers that get taxis.

[tex]\pi(0)=\frac{1}{3}[/tex]

b)

Generally the  average number of taxis X waiting is mathematically given by

[tex]X=1-\pi(0)\\X=1-(1/3)[/tex]

[tex]X=\frac{2}{3}[/tex]