Find l.
10 in.
l
l = [?] ir
1
1
6 in.

Answer:
[tex]l=\sqrt{109}[/tex] in
Step-by-step explanation:
[tex]l^{2} =r^{2} +h^{2} \\\\l^{2} =3^{2} +10^{2} \\\\=90+100\\\\l^{2} =109\\\\l=\sqrt{109}[/tex]
hope it helps....