Below, the two-way table is given for a class of students. Juniors Seniors Free Freshmen Sophomore Male 4 6 2 2. Female 3 4 6 3 Total If a student is selected at random, find the probability the student is a junior given that it's male. Round to the nearest whole percent.​

Respuesta :

Answer:

[tex]Pr = 7\%[/tex]

Step-by-step explanation:

Given

See attachment for graph

Required

Find P(Junior|Male)

To do this, we first calculate the total students.

[tex]Total = 4 + 6 + 2 + 2 + 3 + 4 + 6 + 3[/tex]

[tex]Total = 30[/tex]

Next, select the value in the cell that intersects Male and Junior

[tex]Male\ and\ Junior = 2[/tex]

Hence, the probability is

[tex]Pr = \frac{Male\ and\ Junior}{Total}[/tex]

[tex]Pr = \frac{2}{30}[/tex]

[tex]Pr = 0.067[/tex]

Express as percentage

[tex]Pr = 0.067*100\%[/tex]

[tex]Pr = 6.7\%[/tex]

Approximate

[tex]Pr = 7\%[/tex]

Ver imagen MrRoyal

Answer:

14%

Step-by-step explanation:

2(junior males) out of 14 (the total of males) is 14.29%, which is rounded to a whole percent of 14%. Hope this helps!

p.s. (I was on the same problem on acellus and figured it out. It took forever though)