Suppose that two electronic components in the guidance system for a missile operate independently and that each has a length of life governed by the exponential distribution with mean 1 (with measurements in hundreds of hours). Find the probability density function for the average length of life of the two components.

Respuesta :

Answer:

The probability density function for the average length of life of the two components is [tex]f(x) = 0.5e^{-0.5x}[/tex]

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following probability density:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

Each missile has a length of life governed by the exponential distribution with mean 1 (with measurements in hundreds of hours). Find the probability density function for the average length of life of the two components.

2, each with mean 1 means that [tex]m = 2*1 = 2, \mu = \frac{1}{2} = 0.5[/tex]

So the probability density function is:

[tex]f(x) = 0.5e^{-0.5x}[/tex]