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What is the equation in slope-intercept form of the line that passes through the point(-4,7) and is perpendicular to y=4x+15

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

First find the slope of the line y =4x + 15

slope = 4

Slope of the required line = -1/m = -1/4

(-4 , 7)

Slope point form: y - y1 = m(x - x1)

[tex]y - 7 = \frac{-1}{4}(x - [-4])\\\\y -7 = \frac{-1}{4}(x + 4)\\\\y - 7 =\frac{-1}{4}x + 4*\frac{-1}{4}\\\\y - 7 =\frac{-1}{4}x-1\\\\y = \frac{-1}{4}x - 1 + 7\\\\y = \frac{-1}{4}x + 6[/tex]

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