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A swimming pool in the shape of a cylinder with a diameter of 10 m and a depth of 3 m is being filled with water. 27,535 L have been added so far. 1 m3 is equal to 1000 L. To the nearest liter, how much more water can the pool hold?

A. 236,000 L
B. 208,084 L
C. 236,616 L
D. 207,314 L

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Answer:

207,314

Step-by-step explanation:

V = πr2h =π  · 52·3 ≈ 235.61945 m^3

because 1m^3 = 1000 L, (27,535 / 1000) = the amount of added water in m^3. As this is equal to 27.535, we can substract this from 235.62.

235.62 - 27.535  is about 208.085, or 207.314 because of rounding. As this is in m^3, we multiply by liters to arrive at the answer of 207,314, or option D.

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