Answer:
[tex]ClO^-\\\\Sr^{2+}[/tex]
Explanation:
Hello there!
In this case, according to the reaction between hypochlorous acid and strontium hydroxide which yields stontium hypochlorite and water as a neutralization reaction:
[tex]2HClO(aq)+Sr(OH)_2(aq)\rightarrow Sr(ClO)_2(aq)+2H_2O(l)[/tex]
Thus, since HClO is a weak acid, it is not fully ionized so the complete ionic equation turns out to be:
[tex]2H^++2ClO^-+Sr^{2+}+2(OH)^-\rightarrow Sr^{2+}+2(ClO)^-+2H_2O(l)[/tex]
Whereas the spectator ions, which remain the same at both sides of the equation, are:
[tex]ClO^-\\\\Sr^{2+}[/tex]
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