Answer:
6.726 m/s
Explanation:
Given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
W = fd.
W = 870 * 0.013
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
K.E = 1/2mv²
Where K.E = 11.31
11.31 = 1/2 * 0.5 * v²
22.62 = 0.5v²
v² = 45.24
v = √45.24
v = 6.726 m/s
To break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
Speed is defined as the distance traveled by any object with respect to the time.
Now it is given that
Applied force, F = 870 N
Distance moves by the force, d = 1.3 cm = 0.013 m
Mass of the hand, m = 0.50 kg
From the given values, first thing is to find the work done by the force. Work done is given as
[tex]W=F\times d[/tex]
[tex]W=870\times 0.013[/tex]
W = 11.31 J
To find the velocity, next we use the formula for finding Kinetic Energy
[tex]KE=\dfrac{1}{2}mv^2[/tex]
Where K.E = 11.31
[tex]11.31=\frac{1}2}\times 0.5\times v^2[/tex]
[tex]0.5v^2=22.62[/tex]
[tex]v^2=45.24[/tex]
[tex]v=6.726\ \ \frac{m}{s}[/tex]
Hence to break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]
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