Answer:
[tex]c=0.309\ J/g^{\circ} C[/tex]
Explanation:
The increase in heat, Q = 58.1 J
Mass, m = 89.4 g
The temperature increases from 23.4°C to 25.5°C. We need to find the specific heat of an unknown metal.
We know that the increase in heat is given by :
[tex]Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{58.1}{89.4\times (25.5-23.4)}\\\\c=0.309\ J/g^{\circ} C[/tex]
So, the specific heat of an unknown metal is equal to [tex]0.309\ J/g^{\circ} C[/tex].
