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1.35 m solution NaOCl in water is prepared. What is the mole fraction of the NaOCl?

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Ankit

Answer:

NaOCl + H2O → HOCl + NaOH

so the mole fraction is = moles of NaOCl/(moles of NaOCl+moles of H2O)

so for 1.35 NaOCl it will require 1.35 moleof H2O

mole fraction = 1.35/(1.35+1.35)

mole fraction = 1/2 =0.5

is it correct i d ek but i tried :)

Eduard22sly

The mole fraction of the NaOCl is 0.0237

We'll begin by calculating the mole of solute (NaOCl) in the solution.

  • Molality = 1.35 m
  • Mass of water = 1 Kg
  • Mole of NaOCl =?

Mole = Molality x mass (Kg) of water

Mole of NaOCl = 1.35 × 1

Mole of NaOCl = 1.35 mole

Next, we shall determine the mole of water.

  • Mass of water = 1 Kg = 1000 g
  • Molar mass of water = 18.01 g/mol
  • Mole of water =?

Mole = mass / molar mass

Mole of water = 1000 / 18.01

Mole of water = 55.52 moles

Finally, we shall determine the mole fraction of NaOCl.

  • Mole of NaOCl = 1.35 mole
  • Mole of water = 55.52 moles
  • Total mole = 1.35 + 55.52 = 56.87 moles
  • Mole fraction of NaOCl =?

Mole fraction = mole / total mole

Mole fraction of NaOCl = 1.35 / 56.87

Mole fraction of NaOCl = 0.0237

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