Please help me to do this question with steps

Answer:
x = 71°
Step-by-step explanation:
Segments of tangents from the same external point are congruent, that is
AT = BT
Then Δ ABT is isosceles with base angles congruent , so
x = [tex]\frac{180-38}{2}[/tex] = [tex]\frac{142}{2}[/tex] = 71°