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Calculate the volume of 150kg of chlorine gas at room temperature and pressure. The volume of one mole of gas at room temperature and pressure is 24.0dm^3. Relative formula mass (Mr): Cl2=71​

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Ankit

Answer:

Given mass 150 kg= 150000 gram

molar mass 71 gram

number of moles = given mass/molar mass

= 2112.76 moles

1 mole = 24 Dm³

2112.76 mole =24×2112.76= 50706.24 Dm³

abidemiokin

The volume of the mole of gas at room temperature and pressure is 50,704.08dm³

We need to first calculate the number of moles of Chlorine gas (Cl₂)

Number of moles = Mass/Molar mass

Given the following parameters

The molar mass of Cl₂ = 71g/mol

Mass of chlorine gas = 150kg = 150,000g

Get the number of moles

[tex]n=\frac{150,000}{71}\\n=2,112.67moles\\[/tex]

Given that volume of 1 mole at STP = 24.0dm³

2112.67 moles = x

Get the volume of the chlorine gas at STP.

Volume of Cl₂ at STP = 24 × 2112.67

Volume of Cl₂ at STP = 50,704.08dm³

Hence the volume of the mole of gas at room temperature and pressure is 50,704.08dm³

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