Answer:
m = - [tex]\frac{2}{3}[/tex] , c = - [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 3y + 4 = 0 ( subtract 2x + 4 from both sides )
3y = - 2x - 4 ( divide all terms by 3 )
y = - [tex]\frac{2}{3}[/tex] x - [tex]\frac{4}{3}[/tex] ← in slope- intercept form
with slope m = - [tex]\frac{2}{3}[/tex] and y- intercept c = - [tex]\frac{4}{3}[/tex]
The value of m is -2/3 and c is -4/3
What is equation of a straight line?
Any straight line's general equation is given by the notation y = mx ₊ c, where m denotes the line's gradient(or degree of steepness), and c denotes the y-intercept(a line's intersection with the y-axis).
The linear equation y = mx ₊ c has the form: y = mx ₊ c, where x and y are the variables, and m is the line's coordinates.
The formula y = mx ₊ c allows us to obtain a result for y by entering a value for x.
Y is a dependent variable since it depends on the value of x, which means that x is an independent variable.
Solution:
Given:
2x ₊ 3y ₊ 4 = 0
To Find:
m = slope of the equation
c = y intercept of the equation
Step-1:
The given equation is: 2x ₊ 3y ₊4 = 0
3y = ₋2x ₋ 4
y = ₋2x/3 ₋ 4/3 .............eq(1)
Now, it is in the form y = mx ₊ c ....................eq(2)
Step-2:
On comparing eq(1) and eq(2) we get:
m = ₋2/3 &
c = ₋4/3
Hence we get the value for the slope of the equation as -2/3 and y-intercept of the equation as -4/3.
Learn more about "Linear equations" here-
brainly.com/question/13763238
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