Answer:
400 Joules
Explanation:
From the question,
The total kinetic energy of the water balling when hits the ground is given as
K.E = 1/2mv².................. Equation 1
Where K.E = Kinetic Energy of water ballon, m = mass of water balloon, v = velocity of water ballon
Given: m = 2 kilograms, v = 20 meters/second.
Substitute these values into equation 1
K.E = (2×20²)/2
K.E = 2×400/2
K.E = 400 Joules
