Answer:
E = 3.6 x 10⁷ N/C
Explanation:
The electric field strength due to a point charge is given by the following formula:
[tex]E = \frac{kq}{r^2}\\\\[/tex]
where,
E = Electrical Field Strenght = ?
k = Colomb's Constant = 9 x 10⁹ Nm²/C²
q = magnitude of charge = 10 μC = 1 x 10⁻⁵ C
r = distance = 5 cm = 0.05 m
Therefore,
[tex]E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1\ x\ 10^{-5}\ C)}{(0.05\ m)^2}[/tex]
E = 3.6 x 10⁷ N/C
