Respuesta :

Answer:

132 \: {ft}^{2} 132ft

2

Step-by-step explanation:

Required area = Area of rectangle with dimensions 16 ft and 6 ft + Area of trapezoid with bases (16 - 2 = 14) 14 ft, 10 ft and height 3 ft.

\begin{gathered} = 16 \times 6 + \frac{1}{2} (14 + 10)3 \\ \\ = 96 + \frac{1}{2} \times 24 \times 3 \\ \\ = 96 + 12 \times 3 \\ \\ = 96 + 36 \\ \\ = 132 \: {ft}^{2} \end{gathered}

=16×6+

2

1

(14+10)3

=96+

2

1

×24×3

=96+12×3

=96+36

=132ft

2

Hrishii

Answer:

[tex] 132 \: {ft}^{2} [/tex]

Step-by-step explanation:

Required area = Area of rectangle with dimensions 16 ft and 6 ft + Area of trapezoid with bases (16 - 2 = 14) 14 ft, 10 ft and height 3 ft.

[tex] = 16 \times 6 + \frac{1}{2} (14 + 10)3 \\ \\ = 96 + \frac{1}{2} \times 24 \times 3 \\ \\ = 96 + 12 \times 3 \\ \\ = 96 + 36 \\ \\ = 132 \: {ft}^{2} [/tex]

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