Answer:
Q = -897 kJ/mol
Explanation:
From the given information:
The heat released Q = -65.9 kJ
To start with the molar mass of [tex]H_2O_2[/tex] = 2 × (molar mass of H) + 2 × (molar mass of O)
= (2 × 1.008) + (2 × 16.0 )
= 34.016 g/mol
However, given that:
mass of [tex]H_2O_2[/tex] 2.50 g
The number of moles of [tex]H_2O_2[/tex] = [tex]\dfrac{mass}{molar \ mass}[/tex]
[tex]= \dfrac{2.5}{34.016}[/tex]
[tex]= 7.349 \times 10^{-2} \ mol[/tex]
Finally; Using the formula:
[tex]\Delta H = \dfrac{Q}{number \ of \ moles}\\ \\ Q = \dfrac{-65.9 \ kJ}{7.349 \times 10^{-2} \ mol}[/tex]
Q = -897 kJ/mol
