Answer:
No solution
Step-by-step explanation:
Given
[tex]5x + 3y = 15[/tex]
[tex]10x + 6y = 20[/tex]
Required
Number of solutions
Using elimination method.
First, multiply equation (1) by 2
[tex]5x + 3y = 15[/tex] * 2
[tex]5x * 2 + 3y * 2 = 15 * 2[/tex]
[tex]10x + 6y = 30[/tex]
So, we have:
[tex]10x + 6y = 30[/tex] and
[tex]10x + 6y = 20[/tex]
Subtract both equations
[tex]10x -10x + 6y - 6y = 30 - 20[/tex]
[tex]0+0 = 10[/tex]
[tex]0 = 10[/tex]
The above equation is not true because:
[tex]0 \ne 10[/tex]
Hence, the system of equations has no solution.
