Explanation:
The acid involved is ethanoic acid which is
[tex]CH_3COOH[/tex]
And the alkaline involved is calcium hydroxide which is
[tex]Ca(OH)_2[/tex]
The equation for the reaction is
[tex]Ca(OH)_2 + CH_3COOH → (CH_3COO)_2Ca + H_2O[/tex]
Hope this helps you