The height of a toy rocket launched from 64 foot observation tower function of elapsed time since the launch is modeled in the equation below h(t)=-16t^2+48t+64 at  what approximate elapsed time (s) will the toy rocket be at a height of 90 feet?

Respuesta :

Answer:

69

Step-by-step explanation:

I don't know bro but you are the one who has been a good baby

Answer:

0,70 s

Step-by-step explanation:

We have to solve the associated equation:

-16t^2 + 48t + 64 = 90

1) divide each member by 2

-8t^2 + 24t + 32 = 45

2) add at both member -45

-8t^2 + 24t + 32 -45 = 45-45

-8t^2 + 24t - 13 = 0

3). multiply the two members by -1

8t^2 - 24t + 13 = 0

4) find Δ/4 with the reduce formula

Δ/4 = 144 -104 = 40

5) find the approximate  solutions with the reduce formula

t1 = (12 + 6,42)/8 = 2,29 s

t2 = (12 - 6,42)/8  = 0,70 s

we have to take the smallest value because the biggest describe when the rocket will reach 90 feet when it is descending