use all the tools you have to find the perimeter and area of each shape below

Answer:
Step-by-step explanation:
1)
Area) = area of square + area of triangle
square = 6*6 = 36
area of equilateral triangle = ([tex]\sqrt{3}[/tex] / 4) *a^2 = 31.1759
total area = 36 + 31.1759 = 67.1769[tex]in^{2}[/tex]
Perimeter) 6*5 = 30 "
2)
Area) = upper triangle + lower square
6*[tex]\sqrt{2}[/tex] *sin(45) = 6 cm ( each side is 6)
upper triangle = 1/2*6*6 = 18
lower square = 6*6=36
total area = 38 + 18 = 56 [tex]cm^{2}[/tex]
perimeter = 4*6+6*[tex]\sqrt{2}[/tex] = 32.4852 cm
3)
Area) = left triangle + right rectangle
left triangle = 1/2*3*4 = 6 ( this is the famous 3,4,5 triangle )
rectangle = 8*3 = 24
total area = 24+6=30 [tex]ft^{2}[/tex]
perimeter = 8+5+3+8+3= 27'
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Answer:
Step-by-step explanation:
1. The figure can be decomposed into a square and an equilateral triangle. Both have the same side length: 6 in. For an equilateral triangle of side length s, the area is ...
A = (√3)/4·s²
For a square with side length s, the area is ...
A = s²
The total of the two areas is ...
A = ((√3)/4 + 1)s² ≈ 1.433013×(6 in)²
A ≈ 51.59 in²
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The perimeter is the sum of the 5 equal side lengths:
P = 5(6 in)
P = 30 in
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2. The hypotenuse of the isosceles right triangle at the top of the figure tells you the side length of the triangle is (6√2)/√2 = 6 cm. The area of the triangle is half that of the square below it, so the total area is ...
A = (1 +1/2)(6 cm)²
A = 54 cm²
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The perimeter is the equivalent of 4 sides of 6 cm and one of 6√2 cm, so is ...
P = (4 +√2)(6 cm)
P ≈ 32.49 cm
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3. The triangle at the left end of the figure has a hypotenuse of 5 and a height of 3. It is recognizable as a 3-4-5 right triangle, so the bottom leg of it is 4 ft long. That makes the bottom side of the trapezoid have a length of 8+4 = 12 ft.
The area of the trapezoid is ...
A = 1/2(b1 +b2)h
A = (1/2)(12 ft +8 ft)(3 ft)
A = 30 ft²
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The perimeter is the sum of the side lengths. Starting at left and working clockwise, that sum is ...
P = (5 + 8 + 3 + 12) ft
P = 28 ft