Answer:
t = 0.4 seconds
Explanation:
Given that,
Mass of the object, m = 2 kg
Initial speed of the object, u = 3 m/s
Finally, it stops, v = 0
Constant force applied to the object, F = 15 N
We know that,
Force, F = ma
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s[/tex]
So, it will take 0.4 seconds to stop the mass.
