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What is the magnitude of the electrostatic force between two electrons each having a charge of 1.6 x 10-19 C separated by a distance of 1.00 × l0– 8 meter?

A)
2.56 × 10–22 N
B)
2.30 × 10–20 N
C)
2.30 × 10–12 N
D)
1.44 × 10–1 N

Respuesta :

Answer:

The correct option is (C).

Explanation:

The distance between two charges, [tex]d=10^{-8}\ m[/tex]

We need to find the magnitude of the electrostatic force between two electrons. The formula for the electric force between charges is given by :

[tex]F=\dfrac{kq^2}{r^2}\\\\=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(10^{-8})^2}\\\\=2.304\times 10^{-12}\ N[/tex]

So, the magnitude of force is equal to [tex]2.30\times 10^{-12}\ N[/tex].

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