Answer:
[tex]\Delta T=1.53^{\circ}[/tex]
Explanation:
Given that,
Mass of a lead bullet, m = 0.02 kg
Speed of the bullet, v = 200 m/s
It strikes with an armor plate 2kg at rest. All its kinetic energy is transferred to heat. We need to find the change in temperature.
A/c to the law of conservation of energy,
[tex]\dfrac{1}{2}mv^2=Mc\Delta T\\\\\Delta T=\dfrac{mv^2}{2Mc}\\\\\Delta T=\dfrac{0.02\times 200^2}{2\times 2\times 130}\\\\\Delta T=1.53^{\circ}[/tex]
So, the required change in temperature is equal to [tex]1.53^{\circ}[/tex].
