Given:
The quadratic equation is:
[tex]16x^2-20x-6=0[/tex]
To find:
The correct values for the quadratic formula.
Solution:
If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then the quadratic formula is:
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
We have,
[tex]16x^2-20x-6=0[/tex]
Here, [tex]a=16,b=-20, c=-6[/tex]. Substituting these values in the above quadratic formula, we get
[tex]x=\dfrac{-(-20)\pm \sqrt{(-20)^2^2-4(16)(-6)}}{2(16)}[/tex]
Therefore, the quadratic formula for the given equation is [tex]x=\dfrac{-(-20)\pm \sqrt{(-20)^2^2-4(16)(-6)}}{2(16)}[/tex].
