Answer: The molarity of given solution is 0.476 M.
Explanation:
Given : mass of sample (solute) = 7.0 g
Volume of solution (solvent) = 250 mL
Convert mL into L as follows.
[tex]1 mL = 0.001 L\\ 250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L[/tex]
Molar mass of NaCl is 58.44 g/mol. Hence, moles of NaCl are calculated as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{7.00 g}{58.44 g/mol}\\= 0.119 mol[/tex]
Molarity is the number of moles of a substance present in one liter of solution or solvent.
So, molarity of given solution is calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.119 mol}{0.25 L}\\= 0.476 M[/tex]
Thus, we can conclude that molarity of given solution is 0.476 M.
