Select the correct answer.
What is the solution to this equation?
8(e)^2x+1=4

Answer:
A
Step-by-step explanation:
hello :
8(e)^2x+1=4
(e)^2x+1=4/8 = 1/2
so : 2x+1 = ln(1/2)
2x = ln(1/2) - 1
x = (ln(1/2) - 1)/2
The solution to the given exponential function is x = [ ln(0.5) - 1]/2
The standard exponential equation is expressed as y = ab^x
Given the expression
8(e)^2x+1=4
Divide both sides by 8
(e)^2x+1=4/8
(e)^2x+1 = 1/2
Take the ln of both sides
ln(e)^2x+1 ln(1/2)
2x + 1 = ln(0.5)
2x = ln(0.5) - 1
x = [ ln(0.5) - 1]/2
Hence the solution to the given exponential function is x = [ ln(0.5) - 1]/2
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