Answer: The molarity of final solution is 0.244 M.
Explanation:
Given: [tex]M_{1}[/tex] = 1.00 M, [tex]V_{1}[/tex] = 0.305 L
[tex]M_{2}[/tex] = ?, [tex]V_{2}[/tex] = 1.25 L
Formula used to calculate the molarity f resulting solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\1.00 M \times 0.305 L = M_{2} \times 1.25 L\\M_{2} = \frac{1.00 M \times 0.305 L}{1.25 L}\\= 0.244 M[/tex]
Thus, we can conclude that the molarity of final solution is 0.244 M.
