Answer:
[tex]n_{O_2} =1.207molO_2[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible to calculate the required moles of oxygen by firstly knowing that the molar mass of N2O4 which is 92.011 g/mol and the mole ratio of that product to oxygen is 1:2; in such a way, we proceed as follows:
[tex]n_{O_2}=55.52gN_2O_4*\frac{1molN_2O_4}{92.011gN_2O_4}*\frac{2molO_2}{1molN_2O_4}\\\\n_{O_2} =1.207molO_2[/tex]
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