contestada

A student is conducting molecular weight determination of an unknown diprotic acid. He first prepared a 250 mL of 0.15 M NaOH (39.997 g/mol) titrant solution, which he then standardized with 0.7625 g of KHP (204.22 g/mol) which consumed 26.32 mL of the titrant. After standardization, he weighed 0.0996 g of unknown diprotic acid and the titration reached the endpoint at a volume of 11.68 mL. What is the standardized concentration of titrant?

Respuesta :

Answer:

0.0710

Explanation:

mickymike92

Basedon the data provided, the concentration of the standardized titrant is 0.142 M.

What is a standard solution?

A standard solution is a solution of known concentration.

The concentration of the standardized titrant is calculated from the mole of KHP required.

Moles of KHP = 0.7625 g/ 204.22 g/mol

Moles of KHP = 0.00373 mol

Mole ratio of KHP and NaOH is determined from the equation of the reaction below:

  • NaOH + KHP → KNaP + H2O
  • Mole ratio is 1:1

Therefore, moles of NaOH = 0.00373 moles

Molarity of a NaOH = moles/volume in L

volume of titrant = 26.32 mL = 0.02632 L

Molarity of NaOH = 0.00373/0.02632

Molarity of NaOH = 0.142 M

Therefore, the concentration of the standardized titrant is 0.142 M.

Learn more about standard solution at: https://brainly.com/question/24549357

Otras preguntas