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A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:

a. the force at the support point
b. the force at the left-hand end.

Respuesta :

okpalawalter8

Answer:

[tex]F_l=1140N[/tex]

Explanation:

From the question we are told that:

Length[tex]l=3.00m[/tex]

Support distance [tex]d=1.00m[/tex]

Weight of diver [tex]W_d=500N[/tex]

Weight of board [tex]W_b=280N[/tex]

Generally the equation for Total Torque is mathematically given by

 [tex]F_T=W_d-W_b[/tex]

 [tex]F_T=F_d-f_b[/tex]

 [tex]F_T=-280-500[/tex]

 [tex]F_T=-780[/tex]

 [tex]F_T=780[/tex]

Since we consider the horizontal axis

 [tex]\sum Y=0[/tex]

 [tex]Fs-(\frac{1}{2}l*w_b)-(l-w_d)[/tex]

 [tex]Fs-1.5*280-3*300=0[/tex]

 [tex]F_s=1920N[/tex]

Therefore  the force at the support point  1.00m from the force at the left-hand

 [tex]F_l=F_s-F_l[/tex]

 [tex]F_l=1920-780[/tex]

 [tex]F_l=1140N[/tex]

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