Respuesta :
Answer: [tex]\$5500, \$14,500[/tex]
Step-by-step explanation:
Given
[tex]\$20,000[/tex] is invested in two accounts with a 12% and 11% rate of interest.
Total interest after a year is [tex]\$2255[/tex]
Suppose x amount is invested in first, so the remaining amount is invested in other
Simple interest and Compound interest is the same for a year
[tex]\therefore \text{Interest}=\dfrac{P\times R\times T}{100}[/tex]
For first investment
[tex]I=\dfrac{x\times 12\times 1}{100}\\\\I=0.12x[/tex]
For second investment
[tex]II=\dfrac{\left(20,000-x\right)\times 11\times 1}{100}\\\\II=0.11\left(20,000-x\right)[/tex]
The sum of the two must be [tex]\$2255[/tex]
[tex]\Rightarrow 0.12x+0.11\left (20,000-x\right)=2255\\\Rightarrow 0.01x=2255-2200\\\\\Rightarrow x=\dfrac{55}{0.01}\\\\\Rightarrow x=\$5500[/tex]
Remaining amount is
[tex]\Rightarrow 20,000-5500\\\Rightarrow \$14,500[/tex]
