Respuesta :

Answer: The balanced equation is [tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex].

Explanation:

The given reaction equation is as follows.

[tex]Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}[/tex]

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • [tex]NO_{3}[/tex] = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • [tex]NO_{3}[/tex] = 1

To balance this equation, multiply Li by 2 and [tex]HNO_{3}[/tex] by 2 on reactant side. Also, multiply [tex]LiNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex]

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • [tex]NO_{3}[/tex] = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • [tex]NO_{3}[/tex] = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is [tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex].