Answer:
sec(∠F) = [tex]\frac{41}{9}[/tex]
Step-by-step explanation:
In triangle EFD,
m∠F = 90°
Adjacent side of ∠E = EF = 9 units
Opposite side of ∠E = DF = 40 units
Hypotenuse = DE = 41 units
For secant of ∠E ,
sec(∠E) = [tex]\frac{\text{Hypotenuse}}{\text{Adjacent side}}[/tex]
= [tex]\frac{41}{9}[/tex]
Therefore, [tex]\frac{41}{9}[/tex] is the ratio of secant of ∠F.
