What is the equation of the line that passes through (4, 3) and (-4,-1)?

Answer:
[tex]\implies y = \dfrac{1}{2}x + 1 [/tex]
Step-by-step explanation:
Given :-
And we need to find out the equation of the line passing through the given two points .So here we can use the two point form of the line as ,
[tex]\implies (y - y_1) = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1) [/tex]
Let us take that ,
Now substitute the respective values ,
[tex]\implies (y -3) =\dfrac{3+1}{4+4}(x-4) \\\\\implies y - 3 =\dfrac{4}{8}(x-4) \\\\\implies y -3=\dfrac{1}{2}(x-4) \\\\\implies y -3=\dfrac{1}{2}x - 2 \\\\\implies y = \dfrac{1}{2}x +3-2\\\\\implies y = \dfrac{1}{2}x + 1 [/tex]
Hence the correct option is (2) .