Answer:
Step-by-step explanation:
the area of the hemisphere is 1/2 [tex]\pi[/tex][tex]r^{2}[/tex]
the radius is 1/2 the diameter,
the diameter is also the hypotenuse of the isosceles triangle
[tex]d^{2}[/tex] = [tex]4^{2}[/tex]+[tex]4^{2}[/tex]
[tex]d^{2}[/tex] = 32
d =[tex]\sqrt{32}[/tex]
r = 1/2[tex]\sqrt{32}[/tex]
1/2[tex]\pi[/tex](1/2[tex]\sqrt{32}[/tex])^2
1/2[tex]\pi[/tex](1/4*32)
(32/8 )*[tex]\pi[/tex]
4[tex]\pi[/tex] ( the entire upper hemisphere )
area of the triangle is 1/2* 4 *4 = 8
then the exact area of the parts of the circle would be
4[tex]\pi[/tex] - 8
