Answer:
The solutions for this quadratic equation are [tex]m_1 = 1.94, m_2 = -2.19[/tex]. Bhaskara was used to solve.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
In this question:
We have the quadratic equation:
[tex]4m^2 + m - 17 = 0[/tex], which has [tex]a = 4, b = 1, c = -17[/tex].
Then
[tex]\Delta = (1)^{2} - 4(4)(-17) = 273[/tex]
[tex]m_{1} = \frac{-1 + \sqrt{273}}{8} = 1.94[/tex]
[tex]m_{2} = \frac{-1 - \sqrt{273}}{8} = -2.19[/tex]
The solutions for this quadratic equation are [tex]m_1 = 1.94, m_2 = -2.19[/tex]. Bhaskara was used to solve.
