Answer:
253
Step-by-step explanation:
Given
[tex]J = 9[/tex] --- Jenna's dog
[tex]A = 2277[/tex] -- Animal Shelter
See comment for proper format of the question
Required
How many times did A use than J
The options are not clear. So, the general solution is as follows.
To solve this, we simply divide the chew toys used in A by the chew toys used by J
So, we have:
[tex]n = \frac{A}{J}[/tex]
This gives:
[tex]n = \frac{2277}{9}[/tex]
[tex]n = 253[/tex]