Answer:
The object was dropped at a height of 338.1 meters.
Step-by-step explanation:
According to the statement, the function velocity ([tex]v[/tex]), in meters per second, in term of the initial height of the object ([tex]h[/tex]), in meters, is represented by:
[tex]v = \sqrt{19.6\cdot h}[/tex] (1)
This formula represents a particular case of a free fall analyzed by means of the Principle of Energy Conservation. If we know that [tex]v = 81.4\,\frac{m}{s}[/tex], then the height of the object before being dropped is:
[tex]h = \frac{v^{2}}{19.6}[/tex]
[tex]h = 338.059\,m[/tex]
The object was dropped at a height of 338.1 meters.
