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Consider the following reaction: 2 SO2(g) + O2(g) → 2SO3(g)

If the initial rate of change for sulfur dioxide is -2.00 M/min, what is the initial rate of change of oxygen?

A) -4.00 M/min
B) -1.00 M/min
C) 4.00 M/min
D) 1.00 M/min

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Answer:

B) -1.00 M/min

Explanation:

Based on the reaction:

2 SO2(g) + O2(g) → 2SO3(g)

2 moles of SO2 are consumed per mole of O2 producing 2 moles SO3

In the problem, the sulfur dioxide has a rate of change of -2.00M/min. As the moles of oxygen that reacted are half the moles of SO2, its rate of change is halved, that is:

B) -1.00 M/min

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