Respuesta :
Answer: The correct answer would be C
Step-by-step explanation:
- The snow cone has a conic format.
- The bubble gum has a spherical format.
- The snow cone is filled with bubble gum and with flavored ice.
- Thus, the volume of the cone that can be filled with flavored ice is the volume of the cone subtracted by the volume of the bubble gum.
- To find the volumes, we need to know the formulas for the volume of a cone and the volume of an sphere.
Doing this, we get that the correct option is: 1 / 3(3.14)(3²)(5) − 4 / 3(3.14)(0.55³)
Volume of a cone:
The volume of a cone of height h, with base having radius r, is:
[tex]V = \frac{\pi r^2h}{3}[/tex]
Volume of a sphere:
The volume of a sphere of radius r is given by:
[tex]V = \frac{4\pi r^3}{3}[/tex]
Cone:
- Radius of 3 inches, so [tex]r = 3[/tex].
- Height of 5 inches, so [tex]h = 5[/tex]
Thus, the volume of the cone is:
[tex]V_c = \frac{\pi r^2h}{3} = \frac{(3.14)(3)^2(5)}{3}[/tex]
Sphere:
- Diameter of 1.1 inches.
- Radius is half the diameter, thus, [tex]r = \frac{1.1}{2} = 0.55[/tex]
Thus, the volume of the sphere is:
[tex]V_s = \frac{4\pi r^3}{3} = \frac{4(3.14)(0.55)^3}{3}[/tex]
Volume of the cone that can be filled with flavored ice?
Total(cone) - bubble gum(sphere). Thus:
[tex]V = V_c - V_s[/tex]
[tex]V = \frac{(3.14)(3)^2(5)}{3} - \frac{4(3.14)(0.55)^3}{3}[/tex]
And the correct option is: 1 / 3(3.14)(3²)(5) − 4 / 3(3.14)(0.55³)
A similar question is given at https://brainly.com/question/16606259
