Let A be a matrix with independent rows. A. Show that AAT is invertible. B. Show that if b is any vector in Col(A), then the equation Ax = b has a solution in Row(A) given by xR = AT (AAT )−1 b. (The matrix AT (AAT )−1 is called the pseudoinverse of A, and is usually denoted by A+ . It is a right inverse of A, and coincides with the two-sided inverse A−1 if A is square.) c. The mapping of Col(A) to Row(A) given by xR = AT (AAT )−1 b is an isomorphism

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batolisis batolisis · Answer 1 · 2021-05-28T10:41:41+02:00

Answer:

Attached below

Step-by-step explanation:

Given that A is a matrix with independent rows

A) Prove [tex]AA^{T}[/tex] is invertible

rank of A = number of rows of Matrix A

This shows that | A | ≠ 0 ( i.e. A has a full rank )

also [tex]|A^{T} |[/tex] ≠ 0

and [tex]|AA^{T}|[/tex] = | A | [tex]|A^{T} |[/tex] ≠ 0

Hence we can conclude that [tex]AA^{T}[/tex] is invertible

B) Prove that b is any vector in Col( A )

Attached below is the detailed solution

C) Mapping of Col ( A ) to Row ( A )

b is a non-zero vector hence AXr = 0 ( i.e. there is no solution )

also the kernel of the mapping will be Null

show that mapping preserves the operation

attached below is the detailed solution