Answer: 88
Step-by-step explanation:
Given
The first row has 16 seats
then there are 3 more seats in each row
this follows an AP with the first term [tex]a=16[/tex] and common difference [tex]d=3[/tex]
So, no of seats in the 25 th row is
[tex]\Rightarrow a_{25}=a+24d\\\Rightarrow a_{25}=16+3\times 24\\\Rightarrow a_{25}=88[/tex]
Thus, there are 88 seats in the 25 th row
