The areas of the parallelogram CDEF and triangle EBF can be calculated
from which the difference between the areas can be found.
Response:
- The amount by which the area of parallelogram CDEF is greater than the area of triangle BF is C. 493.5 cm².
Which methods can be used to evaluate the areas of the regular shapes?
Area of the parallelogram CDEF = CF × EB
Which gives;
Area of the parallelogram CDEF, A = 29 cm × 21 cm = 609 cm²
Area of triangle EBF = [tex]\mathbf{\frac{1}{2}}[/tex] × BF × EB
Which gives;
Area of triangle EBF, [tex]A_{EBF}[/tex] = [tex]\frac{1}{2}[/tex] × 11 cm × 21 cm = 115.5 cm²
The difference in area, ΔA = A - [tex]\mathbf{A_{EBF}}[/tex]
Which gives;
ΔA = 609 cm² - 115.5 cm² = 493.5 cm²
- The area of parallelogram CDEF is 493.5 cm² greater than the area of triangle BF
- The correct option is C. 493.5 cm²
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