Line AC intersects line EB at point F. Ray FD extends from point F. Determine the measures of ∠EFD and ∠CFD.

Answer:
see below
Step-by-step explanation: 5 25 7 26
∠AFE is 85° so ∠EFC will equal 180° - 85° = 95°
remember if a right angle is 90° and two right angles is 180° which is just the angle of a line
now we need to solve for x in the following equation
6x - 20 + 2x + 19 = 95
8x - 1 = 95
8x - 1 + 1 = 95 +1
8x = 96
8x / 8 = 96 / 8
x = 96/8
x = 12
now use x = 12 to solve for ∠EFD and ∠CFD
∠EFD = 6x - 20
∠EFD = 6(12) - 20
∠EFD = 52°
∠CFD = 2x + 19
∠CFD = 2(12) + 19
∠CFD = 43°