Respuesta :
Answer:
Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], you can use a normal distribution to approximate the binomial distribution.
The mean is of 11.1 and the standard deviation is of 2.64.
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Using the normal distribution to approximate the binomial distribution.
This is possible if:
[tex]np \geq 10, n(1-p) \geq 10[/tex]
A survey of U.S. adults found that 37% have been to court. You randomly select 30 U.S.
This means that [tex]p = 0.37, n = 30[/tex]
Test if it is possible:
[tex]np = 30*0.37 = 11.1[/tex]
[tex]n(1-p) = 30*0.63 = 18.9[/tex]
Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], you can use a normal distribution to approximate the binomial distribution.
Mean and standard deviation:
[tex]E(X) = np = 30*0.37 = 11.1[/tex]
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.37*0.63} = 2.64[/tex]
The mean is of 11.1 and the standard deviation is of 2.64.
