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A man drops a ball from the top of a 300 foot cliff. The height of the falling ball is modeled
by h(t)=-16t2+300 where h is in feet and t is in seconds. How long does it take for the ball to be 44 feet above the ground?

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altavistard

Answer:

The ball reaches 44 ft above the ground after 4 sec.

Step-by-step explanation:

Set h(t)=-16t^2+300 equal to 44 feet and solve for time, t.  Indicate exponentiation with " ^ "

-16t^2 + 300 = 44 becomes

-16t^2 + 256 = 0, or 16t^2 = 256.  Then, taking the square root of both sides, we get:

4t = 16, or t = 4 sec.  The ball reaches 44 ft above the ground after 4 sec.

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