-59 Points!-

Below, the two-way table is given for a class of students.

^^^^^ (photo attached)

If a student is selected at random, find the
probability the student is a senior given that it's
female. Round to the nearest whole percent.
[?]%

59 Points Below the twoway table is given for a class of students photo attached If a student is selected at random find the probability the student is a senior class=

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Answer:

Solution given:

total female [T]=3+4+6+3=16

n[senior female]=3.

probability the student is a senior given that it's

female:[tex] \frac{n[senior female]}{total [T]} [/tex]

:[tex] \frac{3}{16} [/tex]

:[tex] \frac{3}{16} [/tex] is a probability.

Now percentage::[tex] \frac{3}{16}*100% [/tex]=18.75=19%

Answer:

18.75%. Rounding up: 19%

Step-by-step explanation:

From the table : Total Females = 3+4+6+3 = 16

Number of female seniors = 3

If a student is selected at random find the probability the student is a senior given that it's a female:

P(Female | senior) = number of female seniors / total female  = 3/16 = 0.1875

In percent, 3/16 * 100 = 0.1875 * 100 = 18.75%

the probability the student is a senior given that it's a female.  = 18.75%, which round to nearest whole percent is 19%.